Answer:
See below for answers and explanations
Step-by-step explanation:
Part A
The average rate of change of a function over the interval [tex][a,b][/tex] is equal to [tex]\frac{f(b)-f(a)}{b-a}[/tex], hence:
[tex]\frac{f(b)-f(a)}{b-a}\\\\\frac{f(9)-f(5)}{9-5}\\\\\frac{14-(-4)}{9-5}\\ \\\frac{14+4}{4}\\ \\\frac{18}{4}\\ \\\frac{9}{2}[/tex]
Therefore, the average rate of change of [tex]f(x)[/tex] over the interval [tex][5,9][/tex] is [tex]\frac{9}{2}[/tex].
Part B
Do the same thing as in Part A:
[tex]\frac{f(b)-f(a)}{b-a}\\ \\\frac{f(1)-f(0.25)}{1-0.25}\\ \\\frac{2-5}{0.75}\\ \\\frac{-3}{0.75}\\ \\-4[/tex]
Therefore, the average rate of change of [tex]g(x)[/tex] over the interval [tex][0.25,1][/tex] is [tex]-4[/tex].
Part C
To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).