Question

Can i get some help With This Please

Answer 1

Step-by-step explanation:

See the solution for each part

1)

• f(-2) = - 3(-2) - 6 = 6 - 6 = 0

2)

• g(3) = 3² + 4 = 9 + 4 = 13

3)

• f(g(x)) = -3(x² + 4) - 6 = - 3x² - 12 - 6 = - 3x² - 18

4)

• f(g(3)) = f(13) = - 3(13) - 6 = - 39 - 6 = - 45

5)

• x = - 3f⁻¹(x) - 6
• 3f⁻¹(x) = - x - 6
• 3f⁻¹(x) = -(x + 6)
• f⁻¹(x) =  - (x + 6)/3

Answer 2

• f(x)=-3x-6
• g(x)=x²+4

Now

• f(-2)=-3(-2)-6=6-6=0
• g(3)=3²+4=9+4=13
• f(g(x))=-3(x²+4)-6=-3x²-12-6=-3x²-18
• f(g(3))=-3(3)^2-18=-27-18=-45