GOT ANOTHERONE DUE IN 6 MIN PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!
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[tex]\bold{\huge{\underline{ Solution }}}[/tex]
Here, We have
We know that,
Area of rectangle
[tex]\bold{\red{ = Length {\times} Breath }}[/tex]
Subsitute the required values,
Area of large rectangle
[tex]\sf{ = 12 {\times} 8 }[/tex]
[tex]\sf{ = 96 \:units^{2}}[/tex]
Thus, The area of large rectangle is 96 units² .
Area of non - shaded rectangle
[tex]\sf{ = 9 {\times} 4 }[/tex]
[tex]\sf{ = 36\: units^{2}}[/tex]
Thus, The area of non shaded rectangle is 36 units² .
Area of shaded region
= Area of large rectangle - Area of non shaded rectangle
Subsitute the required values,
[tex]\sf{ = 96 - 36}[/tex]
[tex]\sf{ = 60\: units^{2}}[/tex]
Hence, The total area of shaded region is 60 sq.units.
➾Length(L) of bigger rectangle = [tex]\sf{9+3\: =\:12}[/tex]units.
➾Length(l) of smaller rectangle = 9units.
➾Breadth (B) of bigger rectangle = [tex]\sf{4+4 \:=\: 8}[/tex]units.
➾Breadth(b) of smaller rectangle = 4 units.
➾Area of the shaded region.
➾We can find the area of shaded region by subtracting area of smaller rectangle from area of bigger rectangle(that is whole rectangle including shaded and non shaded region).
So,
➾Area of bigger rectangle = [tex]\sf{L×B}[/tex](putting the value of L and B from the above given)
= [tex]\sf{8×12}[/tex]
= [tex]\sf{96unit^2}[/tex]
Similarly,
➾Area of smaller rectangle = [tex]\sf{l×b}[/tex](putting the value of l and b from the above given)
= [tex]\sf{9×4}[/tex]
= [tex]\sf{36unit^2}[/tex]
Now,
➾Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.
[tex]\sf{= 96-36}[/tex]
[tex]\sf{= 60unit^2.}[/tex]
Therefore, area of shaded region[tex]\sf{= 60unit^2.}[/tex]
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Hope it helps you:)