Question

Write an equation in slope-intercept form for the line that passes through (6,6) and is
perpendicular to the line described

Answer 1

Answer:

Step-by-step explanation:

Solution :

Hello:

an equation   for the line is : y =mx +b    (m: is a slope )

perpendicular to the line described by : y = 2/3 x -2

So : product for two slopes = -1   means : m×2/3=-1

m = -3/2

now : y = -3/2 x+b

but this line :

through the point (6,6) : 6 =(-3/2)(6)+b....... b=15

conclusion :

the equation is : y = -3/2x +15