Question

A body of mass 5kg is ejected vertically from the ground when a force of 600N acts on it for 0.1s.Calculate the velocity with which the body leaves the ground.​

Answer 1

1200

Explanation:

F = m x (v / t)

v / t = F / m

v = (F / m) / t

v = (600 / 5) / 0.1

v = 120 / 0.1

v = 1200 m / s