Use the standard normal distribution to find P(-1.23 Sz<2.12).
![Use the standard normal distribution to find P123 Szlt212 class=](https://us-static.z-dn.net/files/d25/fb32ab0e4301c5c21016f31b55798558.png)
Answer:
(d) 0.8736
Step-by-step explanation:
Unless you have a table of the normal distribution available, this is a calculator problem. Your calculator, or any spreadsheet, can tell you the probability is ...
P(-1.23 ≤ z ≤ 2.12) ≈ 0.8736