Question

NEED HELP!
What is the zero of the function?
f (x) = x2+x-42/x2+3x-28
Enter your answer in the box.

Answer 1

$f(x)=\cfrac{x^2+x-42}{x^2+3x-28}\implies \stackrel{f(x)}{0}=\cfrac{x^2+x-42}{x^2+3x-28}\implies 0 = x^2+x-42 \\\\\\ 0=(x+7)(x-6)\implies x= \begin{cases} 6\\ -7 \end{cases}$

Answer 2

x
≈
−
6.3630657
,
−
1.38899554
,
4.75206125