Respuesta :

Answer:

[tex]\displaystyle 14 = x[/tex]

Step-by-step explanation:

Use the Pythagorean Theorem to define the hypotenuse:

[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ -48^2 + 50^2 = x^2 \hookrightarrow -2304 + 2500 = x^2 \hookrightarrow \sqrt{196} = \sqrt{x^2} \\ \\ \boxed{14 = x}[/tex]

I am joyous to assist you at any time.

[tex] \huge \underline\text{ Hello There}[/tex]

[tex] \text{We know, Pythagoras Theorem}[/tex]

[tex]\implies \text{ (Hypotenuse)²= (Base)² + (Altitude)²}[/tex]

[tex] \text{Here, \red{Hypotenuse}= 50, \red{Base}= x, \red{Altitude}= 48}[/tex]

[tex] \underline \text{To Find, } \text{Value of'x'}[/tex]

[tex] \huge \underline\text \red {Solution}[/tex]

[tex] \implies(50) {}^{2} = {(x)}^{2} + (48) {}^{2} \\ \implies2500 = (x) {}^{2} + 2304[/tex]

[tex] \implies (x) {}^{2} = 2500 - 2304 \\ \implies (x) {}^{2} = 196 \\ \implies x = \sqrt{196} \\ \implies x = 14[/tex]

[tex] \therefore \text{Base}= 14[/tex]

Hope this helps

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