please help me I would be so happy
Find the missing side of the triangle.

Answer:
[tex]\displaystyle 14 = x[/tex]
Step-by-step explanation:
Use the Pythagorean Theorem to define the hypotenuse:
[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ -48^2 + 50^2 = x^2 \hookrightarrow -2304 + 2500 = x^2 \hookrightarrow \sqrt{196} = \sqrt{x^2} \\ \\ \boxed{14 = x}[/tex]
I am joyous to assist you at any time.
[tex] \huge \underline\text{ Hello There}[/tex]
[tex] \text{We know, Pythagoras Theorem}[/tex]
[tex]\implies \text{ (Hypotenuse)²= (Base)² + (Altitude)²}[/tex]
[tex] \text{Here, \red{Hypotenuse}= 50, \red{Base}= x, \red{Altitude}= 48}[/tex]
[tex] \underline \text{To Find, } \text{Value of'x'}[/tex]
[tex] \huge \underline\text \red {Solution}[/tex]
[tex] \implies(50) {}^{2} = {(x)}^{2} + (48) {}^{2} \\ \implies2500 = (x) {}^{2} + 2304[/tex]
[tex] \implies (x) {}^{2} = 2500 - 2304 \\ \implies (x) {}^{2} = 196 \\ \implies x = \sqrt{196} \\ \implies x = 14[/tex]
[tex] \therefore \text{Base}= 14[/tex]