An athlete is holding 24 lb of weights at a height of 6 inches above the stack as shown. To lower the weights, she applies a constant force of 5 lb to the handle. Determine the velocity of the weights immediately before they hit the stack.

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ogorwyne ogorwyne · Answer 1 · 2022-04-05T16:41:56+02:00

The velocity of the weights immediately before they hit the stack is 3.4672 ft/s

1 Lb = 0.453 kg

24 = 24 x 0.453

= 10.872kg

Therefore the m = 10.872

g = 9.87

m1 = 10.872/9.87

m1g = 1.112

T = 5 lb

= 5 x 0.453 = 2.265kg

m1g = T + 2T

1.112a = 10.872 - 3(2.265)

a = 3.66m/s²

initial velocity = 0

6x 2.54

= 15.24x10⁻²m

v² = 0+ 2as

v = √2as

v = √2x3.66x 15.24x10⁻²

= √1.1174

= 1.0571

a meter is equal to 3.28 ft

v*m = 1.0571 * 3.28

= 3.4672 ft/s

The velocity of the weights immediately before they hit the stack is 3.4672 ft/s.

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