Answer:
[tex]f(x)=\sqrt[3]{x-2} +1[/tex]
Step-by-step explanation:
Given function for graph: [tex]f(x)=1\sqrt[3]{x-h} +k[/tex]
where (h, k) is the midpoint of the curve.
Therefore, the parent function is [tex]f(x)=\sqrt[3]{x}[/tex]
[tex]f(x)=1\sqrt[3]{x-h} +k[/tex] can be obtained by translating [tex]f(x)=\sqrt[3]{x}[/tex] to [tex]h[/tex] units to the right and [tex]k[/tex] units up
The x and y intercept of [tex]f(x)=\sqrt[3]{x}[/tex] is the origin
Therefore, this graph has been translated 2 units to the right and 1 unit up.
Therefore, [tex]h=2[/tex] and [tex]k=1[/tex]
Substituting these values into the given function:
[tex]\implies f(x)=\sqrt[3]{x-2} +1[/tex]
