Respuesta :
9.3 ft³
- height of Prism X is 10 ⅓ ft,
- the volume of Prism X is 74 ⅖ ft³
- height of Prism Y is 5 ⅙ ft.
use the rule:
[tex]\rightarrow \sf (\dfrac{V_1}{V_2} )= (\dfrac{h_1}{h_2} )^3[/tex]
solve:
[tex]\rightarrow \sf (\dfrac{74\frac{2}{5} }{V_2} )= (\dfrac{10\frac{1}{3} }{5\frac{1}{6} } )^3[/tex]
[tex]\rightarrow \sf (\dfrac{74\frac{2}{5} }{V_2} )= (2 )^3[/tex]
[tex]\rightarrow \sf \dfrac{74\frac{2}{5} }{V_2} =8[/tex]
[tex]\rightarrow \sf V_2 = \dfrac{74\frac{2}{5} }{8}[/tex]
[tex]\rightarrow \sf V_2 = 9.3 \ ft^3[/tex]
Answer:
Given:
[tex]\sf Height \ of \ Prism \ X = 10\frac13=\dfrac{(10 \times 3)+1}{3}=\dfrac{31}{3}[/tex]
[tex]\sf Height \ of \ Prism \ Y = 5\frac16=\dfrac{(5 \times 6)+1}{6}=\dfrac{31}{6}[/tex]
[tex]\sf Volume\ of \ Prism \ X = 74\frac25=\dfrac{(74 \times 5)+2}{5}=\dfrac{372}{5}[/tex]
Prism X is a dilation of Prism Y.
⇒ Scale factor of dilation = height of Prism X ÷ height of Prism Y
[tex]\sf =\dfrac{31}{3} \div \dfrac{31}{6}[/tex]
[tex]\sf =\dfrac{31}{3} \times \dfrac{6}{31}[/tex]
[tex]\sf =\dfrac63[/tex]
[tex]\sf =2[/tex]
If Prism X is a dilation of Prism Y by scale factor 2, then Prism Y is a dilation of Prism X by scale factor [tex]\frac12[/tex].
To find the volume of Prism Y, we simply need to multiply the volume of Prism X by the cube of scale factor [tex]\frac12[/tex], since volume is measured in cubic units.
[tex]\sf \implies volume \ of \ Prism \ Y = volume \ of \ Prism \ X \times (scale \ factor)^3[/tex]
[tex]\sf = \dfrac{372}{5} \times \left(\dfrac12\right)^3[/tex]
[tex]\sf = \dfrac{372}{5} \times \dfrac18[/tex]
[tex]\sf =\dfrac{372}{40}[/tex]
[tex]\sf =\dfrac{93}{10}[/tex]
[tex]\sf = 9 \frac{3}{10} \ ft^3[/tex]