Respuesta :

  • Mass=1500g=m
  • ∆T=52-25=27°C
  • Specific heat capacity=c=4.184J/g°C

Apply thermodynamics

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

  • Q is heat

[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]

[tex]\\ \rm\rightarrowtail Q=169452J[/tex]

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