Question

Solve the system of equations

3x + 4y + 2z = 1
4x + 6y + 2z = 7
2x + 3y + z = 11

Answer 1

Answer:

Hindi ko po alam yan sorry

Answer 2

Answer:

no solution

Step-by-step explanation:

$\left\{\begin{matrix}3x+4y+2z=1\\4x+6y+2z=7\\2x+3y+z=11\\\end{matrix}\right.$

Rearrange

$\left\{\begin{matrix}3x+4y+2z=1\\4x+6y+2z=7\\z=11-2x-3y\\\end{matrix}\right.$

Substitute into one of the equations

$\left\{\begin{matrix}3x+4y+2(11-2x-3y)=1\\4x+6y+2(11-2x-3y)=7\\\end{matrix}\right.$

Apply the Distributive Property

$\left\{\begin{matrix}3x+4y+22-4x-6y=1\\4x+6y+22-4x-6y=7\\\end{matrix}\right.$

Apply the Inverse Property of Addition

$6y+22-6y=7$

$\left\{\begin{matrix}3x+4y+22-4x-6y=1\\22=7\\\end{matrix}\right.$

Rearrange variables to the left side of the equation

$\left\{\begin{matrix}3x+4y-4x-6y=1-22\\22=7\\\end{matrix}\right.$

Combine like terms

$\left\{\begin{matrix}-x-2y=1-22\\22=7\\\end{matrix}\right.$

Calculate the sum or difference

$\left\{\begin{matrix}-x-2y=-21\\22=7\\\end{matrix}\right.$

Rearrange like terms to the same side of the equation

$\left\{\begin{matrix}-x=-21+2y\\22=7\\\end{matrix}\right.$

Divide both sides of the equation by the coefficient of variable

$\left\{\begin{matrix}x=21-2y\\22=7\\\end{matrix}\right.$

Based on the given conditions, the (system of) equation(s) has

$no\ solution$

I hope this helps you

:)