Answer:
x = -1
y = -8
Step-by-step explanation:
Given:
[tex]\begin{bmatrix}8x+y=-16\\ -3x+y=-5\end{bmatrix}[/tex]
Solve:
[tex]\mathrm{Substitute\:}x=\frac{-16-y}{8}[/tex]
[tex]\begin{bmatrix}-3\cdot \frac{-16-y}{8}+y=-5\end{bmatrix}[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]\begin{bmatrix}\frac{48+11y}{8}=-5\end{bmatrix}[/tex]
[tex]\mathrm{For\:}x=\frac{-16-y}{8}[/tex]
[tex]\mathrm{Substitute\:}y=-8[/tex]
[tex]x=\frac{-16-\left(-8\right)}{8}[/tex]
[tex]x=-1[/tex]
[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]
[tex]x=-1,\:y=-8[/tex]
~Lenvy~
