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Using simple interest, it is found that:
12. The loan matured after 6 years.
13. The actual interest rate was of 12%.
Simple interest is used when there is a single compounding per time period.
The amount of interest after t years in is modeled by:
[tex]I(t) = Prt[/tex]
In which:
Question 12:
The parameters are: P = 2000, r = 0.06, I = 720, hence:
[tex]I(t) = Prt[/tex]
[tex]720 = 2000(0.06)t[/tex]
[tex]t = \frac{720}{2000 \times 0.06}[/tex]
[tex]t = 6[/tex]
The loan matured after 6 years.
Question 13:
The parameters are: t = 5, P = 4000, r = 0.11.
Hence:
I = 4000 x 0.11 x 5 = 2200.
$200 more was charged in interest, hence I(5) = 2400, and:
[tex]I(t) = Prt[/tex]
[tex]2400 = 4000(5)r[/tex]
[tex]r = \frac{2400}{20000}[/tex]
[tex]r = 0.12[/tex]
The actual interest rate was of 12%.
More can be learned about simple interest at https://brainly.com/question/25296782