Respuesta :

Using simple interest, it is found that:

12. The loan matured after 6 years.

13. The actual interest rate was of 12%.

Simple Interest

Simple interest is used when there is a single compounding per time period.

The amount of interest after t years in is modeled by:

[tex]I(t) = Prt[/tex]

In which:

  • P is the initial amount.
  • r is the interest rate, as a decimal.

Question 12:

The parameters are: P = 2000, r = 0.06, I = 720, hence:

[tex]I(t) = Prt[/tex]

[tex]720 = 2000(0.06)t[/tex]

[tex]t = \frac{720}{2000 \times 0.06}[/tex]

[tex]t = 6[/tex]

The loan matured after 6 years.

Question 13:

The parameters are: t = 5, P = 4000, r = 0.11.

Hence:

I = 4000 x 0.11 x 5 = 2200.

$200 more was charged in interest, hence I(5) = 2400, and:

[tex]I(t) = Prt[/tex]

[tex]2400 = 4000(5)r[/tex]

[tex]r = \frac{2400}{20000}[/tex]

[tex]r = 0.12[/tex]

The actual interest rate was of 12%.

More can be learned about simple interest at https://brainly.com/question/25296782

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