Respuesta :

Lenvy

Answer:

x = 5/3 , y = -1

Step-by-step explanation:

Given:

[tex]\begin{bmatrix}3x+y=4\\ 6x+4y=6\end{bmatrix}[/tex]

Solve:

[tex]\mathrm{Substitute\:}x=\frac{4-y}{3}[/tex]

[tex]\begin{bmatrix}6\cdot \frac{4-y}{3}+4y=6\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}2y+8=6\end{bmatrix}[/tex]

[tex]\mathrm{For\:}x=\frac{4-y}{3}[/tex]

[tex]\mathrm{Substitute\:}y=-1[/tex]

[tex]x=\frac{4-\left(-1\right)}{3}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]x=\frac{5}{3}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=\frac{5}{3},\:y=-1[/tex]

3(5/3) + -1

5-1 = 4

True

6(5/3) + 4(-1)

10 -4 = 6

True

~lenvy~

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