Answer:
x = 3, y = 1
Step-by-step explanation:
Given:
[tex]\begin{bmatrix}x+4y=7\\ 4x-3y=9\end{bmatrix}[/tex]
Solve:
[tex]\mathrm{Substitute\:}x=7-4y[/tex]
[tex]\begin{bmatrix}4\left(7-4y\right)-3y=9\end{bmatrix}[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]\begin{bmatrix}28-19y=9\end{bmatrix}[/tex]
[tex]\mathrm{For\:}x=7-4y[/tex]
[tex]\mathrm{Substitute\:}y=1[/tex]
[tex]x=7-4\cdot \:1[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]x=3[/tex]
[tex]\mathrm{The\:Answer\:to\:the\:system\:of\:equations\:are:}[/tex]
[tex]x=3,y=1[/tex]
Check Answer:
3 + 4(1)
7 (1) = 7
True
4(3) - 3(1)
12 - 3 = 9
True
Hence, x = 3 , y =1
~lenvy~