Question

PLEASE HELP ME! WILL GIVE BRAINLIEST TO BEST ANSWER, THANKS, 5 STARS!

Can someone please explain this to me??

"What is the value of the positive zero of this quadratic $g(x)=x^2+4x-32$?"

Answer 1

Answer:

4

Step-by-step explanation:

$g(x) = {x}^{2} + 4x - 32 \\ plug \: g(x) = 0 \\ \implies \: 0 = {x}^{2} + 8x - 4x - 32 \\ \implies \: 0 = x(x + 8) - 4(x + 8) \\ \implies \: 0 = (x + 8)(x - 4) \\ \implies \: x + 8 = 0 \: \: or \: \: x - 4 = 0 \\ \implies \: x = - 8 \: \: or \: \: x = 4 \\ thus \: the \: value \: of \: positive \: zero \\ is \: 4$