Question

A circuit consists of three resistors in series: one of 3Ω, one of 7Ω and 10Ω. A battery of e. m. f. 12ν and negligible internal resistance is connected to the circuit. What size current will it supply?

Answer 1

Answer:

Explanation:

Remark

The thing to note is that the current is the same through the resistors and the battery.

To accomplish this, the resistors must appear as 1 value to the battery. You can only do that it you add the resistors together.

Resistance

R_total = 3 + 7 + 10 all are in ohms

R_total = 20 ohms

Givens

R = 20

E = 12

I = ?

Formula

I = E/R

Solution

I = 12/20

Answer I = 0,6 amperes.