Answer:
Given:
AB is a diameter
<BOC=<COD
AO=OB=OC=OD being radius
TO PROVE :
AD // OC
CONSTUCTION:
AC is joined:
Proof:
<BOC=2<BAC
<COD=2<DAC
Being center angle is double of the inscribed angle standing on a same arc.
we get
[tex]<DAO=\frac{1}{2}(<BOC+<COD)=\frac{1}{2}(<BOC+<BOC)[/tex]
Given
<DAO=<BOC
which satisfy the property of corresponding angle.
So, AD//OC
proved:
Step-by-step explanation:
