Question

The Lapointe family has 4 kids, 2 boys and 2 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the probability of a girl birth is also 1/2. What is the fractional probability of having 2 boys and 2 girls, in any order, in a family's first 4 births?

Answer 1

Answer: 3/8

Step-by-step explanation:

$\text{Let boy be: A } \\ \text {Let girl be } B \\\\ \mathrm{ A A B B \ \ A B A B \ \ A B B A \ \ B A A B \ \ B A B A \ \ B B A A} \\\\= \frac{6}{16} = \bf{\frac{3}{8}}$