Answer: D
Step-by-step explanation:
[tex]3x^2-x+2=0[/tex]
[tex]\text{Solve \ with \ the \ quadratic \ formula \mathrm{for\:}\quad a=3,\:b=-1,\:c=2}[/tex]
[tex]x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2}}{2\cdot \:3}[/tex] [tex]\rightarrow \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2} =\sqrt{1-24} =\sqrt{-23} =\sqrt{-1}\sqrt{23} =\sqrt{23}i[/tex]
[tex]x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{23}i}{2\cdot \:3}[/tex]
[tex]x_1=\frac{-\left(-1\right)+\sqrt{23}i}{2\cdot \:3},\:x_2=\frac{-\left(-1\right)-\sqrt{23}i}{2\cdot \:3}[/tex]
[tex]x_1=\frac{1+\sqrt{23}i}{6},\:x_2=\frac{1-\sqrt{23}i}{6}[/tex]
