Answer: 0.9
Step-by-step explanation:
[tex]\mathrm{Total \ sample \ space \ $=100$} \\\mathrm{Event \ $A = \ taking \ subway \ each \ day}$P(A)=0.85$Event $B=$ taking taxi $\because P(B)=0.6$$P(A \cap B)=0.55$[/tex]
[tex]\begin{aligned}P(A \cup B) & \Rightarrow \text { Person taking either taxi/subway } \\&=P(A)+P(B)-P(A \cap B) \\&=(0.85-0.555)+(0.6-0.55)-0.55 \\&=1.45-0.55\\&\bf{=0.9} \end{aligned}[/tex]