Answer:
[tex]\huge\boxed{\sf -2.280}[/tex]
Step-by-step explanation:
Finding value of log₃(4/49):
[tex]\displaystyle = log_{3}\frac{4}{49} \\\\= log_{3} (\frac{4}{7^2} )\\\\\underline{Using \ log \ rule \ :} \ log( \frac{a}{b} )= log \ a - log \ b \\\\= log_{3}4 - log_{3}7^2\\\\\underline{Using \ log \ rule \ : } \ log \ a ^m = m \ log \ a \\\\= log_{3}4 - 2(log_{3}7)\\\\[/tex]
Given that:
log₃4 ≈ 1.262, log₃7 ≈ 1.771
Put the values in the above expression
[tex]= 1.262-2(1.771)\\\\= 1.262 - 3.542\\\\= \bold{-2.280}\\\\\rule[225]{225}{2}[/tex]