Respuesta :
Since the equation is not given. To find the 10 partial sums of the series when ∑∞ₙ= ₁ cos(6) is given below:
- The 10 partial sums to be 0.96017, 1.80402, 2.46434, 2.88852, 3.04277, 2.91481, 2.51483, 1.87469, 1.04538 and 0.09297.
What is a Partial Sum?
This is known to be the sum (addition) of a section of the sequence. The addition of infinite terms is known to be an Infinite Series. Partial Sums are often known as Finite Series.
Note that n= 1,2,3,4...10, so we would fit the numbers into the equation given above:
If n = 1, cos(6n) = cos(6) = 0.96017
if n = 2, cos(6n) = cos(12) = 0.84385
if n = 3, cos(6n) = cos(18) = 0.66032
if n = 4, cos(6n) = cos(24) = 0.42418
if n = 5, cos(6n) = cos(30) = 0.15425
if n = 6, cos(6n) = cos(36) = -0.12796
if n = 7, cos(6n) = cos(42) = -0.39998
if n = 8, cos(6n) = cos(48) = -0.64014
if n = 9, cos(6n) = cos(54) = -0.82931
if n = 10, cos(6n) = cos(60) = -0.95241
Since we know what the values of N are, we can then solve for the first 10 partial sums using: We take partial sum to be (S). So therefore:
S1=cos(6)=0.96017
S2=cos(6)+cos(12) =0.9601+0.8439=1.80402
S3=cos(6)+cos(12)+cos(18) =1.804+0.6603=2.46434
S4=cos(6)+cos(12)+cos(18)+cos(24) =2.4643+0.4241=2.88852
S5=cos(6)+cos(12)+cos(18)+cos(24)+cos(30) =2.888+0.1543=3.04277
S6=cos(6)+cos(12)+cos(18)+cos(24)+cos(30)+cos(36)=3.0427-0.1280=2.91481
S7=cos(6)+cos(12)+cos(18)+cos(24)+cos(30)+cos(36)+cos(42)=2.9147-0.3999=2.51483
S8=cos(6)+cos(12)+cos(18)+cos(24)+cos(30)+cos(36)+cos(42)+cos(48) =2.5148-0.6401=1.87469
S9=cos(6)+cos(12)+cos(18)+cos(24)+cos(30)+cos(36)+cos(42)+cos(48)+cos(54) =1.8747-0.8293=1.04538
S10=cos(6)+cos(12)+cos(18)+cos(24)+cos(30)+cos(36)+cos(42)+cos(48)+cos(54)+cos(60) =1.0454-0.9524=0.09297
So therefore, we have the 10 partial sums to be 0.96017, 1.80402, 2.46434, 2.88852, 3.04277, 2.91481, 2.51483, 1.87469, 1.04538 and 0.09297 respectively.
Learn more about partial sums from
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