Respuesta :

I believe question 12 is 8(x+1)(x-1) and question 11 is a(4x-3)(2x+1)

11. [tex]8ax^2-2ax-3a = a(8x^2-2x-3) = a((4x-3)(2x+1))=a(4x-3)(2x+1)[/tex]

12. [tex]8x^2-8=8(x^2-1)=8(x+1)(x-1)[/tex]

Hope that helps!

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