The concentration of NaOH that is used to completely neutralize is 0.25 Liters.
We will calculate the concentration in terms of molarity by using the below formula:
M₁V₁ = M₂V₂, where
M₁ = molarity of H₂SO₄ = 2m
V₁ = volume of H₂SO₄ = 0.25 L
M₂ = molarity of NaOH = ?
V₂ = volume of NaOH = 2 L
On putting all these values on the above equation, we get
M₂ = (2)(0.25) / (2) = 0.25 L
Hence required volume is 0.25 L.
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