Question

Calculate the concentration (in m) of acetate ion in a buffer solution made from 2. 00 ml 2. 00 ml of 0. 50 m acetic acid 0. 50 m acetic acid and 8. 00 ml 8. 00 ml of 0. 50 m sodium acetate 0. 50 m sodium acetate

Answer 1

With 2.0 ml and 0.5 ml of sodium acetate, the concentration of acetate ion in the buffer solution is equal to 0.4ml

How to solve for the concentration in the buffer solution

To solve this the formula to use is

$acetate = \frac{c1+v1}{v2}$

Where c1 = 0.50 acetate ion

v1 = 8 ml of sodium acetate

v2 = 8ml + 2ml = 10 ml

When we out the values into the formula above we would have

$0.5*\frac{8}{10}$

= 0.5 x 0.8

= 0.4 M

The concentration of acetate ion in the buffer solution is equal to 0.4ml

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