Shift 1 unit to the left to perform the translation maps the vertex of f(x) onto the vertex of the function g(x).
It is given that the function [tex]\rm f(x) = x^2[/tex] and function [tex]\rm g(x)= x^2+2x+1[/tex]
It is required to find the translation maps of the vertex of the graph of f(x) onto the vetrex of the graph of g(x).
It is defined as a special type of relationship and they have a predefined domain and range according to the function.
We have two functions first one:
[tex]\rm f(x) = x^2[/tex] and
[tex]\rm g(x)= x^2+2x+1[/tex]
For the function f(x) the vertex is (0, 0) as shown in the graph.
We can write g(x) as a:
[tex]\rm g(x)= x^2+2x+1\\\\\rm g(x) = (x+1)^2[/tex]∵ [tex]\rm (a+b)^2 = a^2+2ab+b^2[/tex]
And the vertex of the graph of g(x) is (-1, 0) [Shown in the graph]
For f(x) vertex point is (0, 0) and
For g(x) vetex point is (-1 , 0)
It is clear that the if shift vertex point f(x) to -1 unit we get (-1, 0) ie.
(x, y) ⇒⇒ (x-1, y)
(0, 0) ⇒⇒ (0-1, 0) ⇒⇒ (-1, 0)
Thus, shift 1 unit to the left to perform the translation maps the vertex of f(x) onto the vertex of the function g(x).
Learn more about the function here:
brainly.com/question/5245372