Answer: f(1) = -4
Step-by-step explanation:
[tex]\mathrm{According \ to \ the \ question, \ when \ $x=1, \ 1{\displaystyle < }4$.} \\$\text { } \begin{aligned}f(1) &=-(x-2)^{2}-3 \\&=-(1-2)^{2}-3 \\&=-(-1)^{2}-3 \\&=-1-3 \\&=-4\end{aligned}$\\Therefore, the answer is $f(1)=-4$.[/tex]
