Question

The equation y-1--7(x-3) is written in point-slope form. What is the y-intercept of the line?

Answer 1

Answer:

22

Step-by-step explanation:

We will be using y = mx + b

m would be the slope

b would be the cut point with the y-axis (aka the y-intercept)

We will take y-1=-7(x-3) into the form of y = mx+b

- x - would be +

y-1= -7x + 21

Take the -1 from the left side to the right side

y = -7x + 21 + 1

y = -7x + 22

b would be 22

The fact that I recently finish with this work a while ago with my teacher.

Hope this helps.

Answer 2

Hey there!

In order to identify the y-intercept of the line, we should first convert the equation of the line (which is written in point-slope form), into slope-intercept form (y=mx+b)

So, let's do it. :)

y-1=-7(x-3)

Distribute -7:

y-1=-7x+21

Add 1 to both sides:

y=-7x+21+1

y=-7x+22

Hence, the y-intercept is

$\boxed{\boxed{\bold{22}}}$

Hope everything is clear.

Let me know if you have any questions!

#LearnWithJoy

$\rm{Someone~Who~Is~Willing~To~Help}$