Question

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Answer 1

Solution:-

➾$\sf{x^2-14x = 6}$

➾$\sf{x^2-14x+30-6 = 0}$

➾$\sf{x^2-14x+24 = 0}$

By using splitting the middle term method:

➾$\sf{x^2-12x-2x+24 = 0 }$

➾$\sf{x(x-12)-2(x-12) = 0}$

➾$\sf{ (x-12)(x-2) = 0}$

Now, if $\sf{(x-12) = 0}$ then,

➾$\sf\blue{x = 12}$

And, if $\sf{(x-2) = 0}$ then,

➾$\sf\blue{ x = 2}$

So, x is equal to either 12 or 2 are the solution of the given equation.