a) The frequency of the wave is 4.0 Hz
b) The period T of the wave is 0.25s
c) The speed of the wave is 12m/s
Given the data in the question;
- Number of oscillation per seconds = 4.0
- Wavelength; [tex]\lambda = 3.0m[/tex]
- Frequency; [tex]f = \ ?[/tex]
- Period; [tex]T = \ ?[/tex]
- Speed of the wave; [tex]v = \ ?[/tex]
Frequency, Period and speed.
Frequency is simply the number of occurrences of a repeating phenomenon per unit time.
Period is the time needed for a complete cycle of vibration to pass a given point.
It is expressed as;
[tex]T = \frac{1}{f}[/tex]
Where f is the frequency
Speed is simply the distance traveled in a given interval of time or time ratio.
It is expressed as;
[tex]v = \lambda * f[/tex]
Where [tex]\lambda[/tex] is wavelength and f is frequency
a) Frequency
We said frequency is the number of occurrences of a repeating phenomenon per unit time.
Since the wave oscillates 4.0 times a second
Hence, the frequency of the wave is 4.0 Hz
b) Period
[tex]Period\ T = \frac{1}{f} \\\\Period\ T = \frac{1}{4.0Hz}\\\\Period\ T = \frac{1}{4.0s^{-1}}\\\\Period\ T = 0.25s[/tex]
Therefore, the period T of the wave is 0.25s
c) Speed
[tex]v = \lambda * f\\\\v = 3.0m * 4.0Hz\\\\v = 3.0m * 4.0s^{-1}\\\\v = 12ms^{-1}\\\\v = 12m/s[/tex]
Therefore the speed of the wave is 12m/s.
Learn more about speed, wavelength and frequency: https://brainly.com/question/27120701
