The block falls for a time t0, but the string does not completely unwind. What is the change in angular momentum of the pulley-block system from the instant that the block is released from rest until time t0?

Respuesta :

The change in angular momentum of the pulley-block system is given as [tex]\omega = Rm_ogt_o[/tex]

Data;

  • time = t0
  • mass = Mo

Torque

This is the force that makes object rotate about an axis. The formula is given as the product between the radius about the axis and the force acting upon it.

The torque about point o is given as

[tex]\tau = R * m_og[/tex]

The change in angular momentum about point 'o' is the product between the torque and time.

[tex]\omega = \tau * t_o\\\omega = Rm_ogt_o[/tex]

The change in angular momentum of the pulley-block system is given as

[tex]\omega = Rm_ogt_o[/tex]

Learn more on torque here;

https://brainly.com/question/16928748

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