The strength of the electric field will be 2.7 x 108 N/C.
The strength of the electric field is the ratio of electric force per unit charge. Its unit is NC⁻¹.
The given data in the problem is;
E is the strength of the electric field =?
d is the distance = 0.020 m
q is the charge= 12 µc =12 ×10⁻⁶C
The electric field strength is given by;
[tex]E = \frac{Kq}{d^2} \\\\E = \frac{9 \times 10^9\times 12 \times 10^{-6}}{(0.020)^2} \\\\E = 2.7 \times 10^8 N/C[/tex]
Hence the strength of the electric field will be 2.7 x 108 N/C.
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