A 10,000 kg freight car moving at 2 m/s collided with a stationary 30,000 kg freight car. The two cars couple together and move off at what speed?

Respuesta :

Answer:

Explanation:

Momentum conservation:

10,000 x 2 = (10,000 + 30,000) x v

so

v = 0.5 m/s

The speed after collision will be = 0.5m/s

What is conservation of momentum ?

The conservation of momentum states that the amount of momentum remains constant , momentum is neither be created nor be destroyed but only changes through the actin of forces as described by newton's law of motion

since , momentum should be conserved before and after the collision

so , from momentum conservation we can write ,

m1 = mass of moving freight car = 10000kg

v1 = speed of moving freight  car = 2m/s

m2 = mass of stationary freight car  = 30000 kg

v2 = speed of stationary freight car   = 0 (since , at rest )

M = mass of coupled cars after collision

V = velocity  coupled cars  after collision

momentum before collision = momentum after collision

m1*v1 + m2*v2 = MV

10000 * (2) + 30,000 * 0 = (10000 + 30000) V

20000 = 40000V

V = 0.5 m/s

The speed after collision will be = 0.5m/s

learn more about conservation of momentum

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