Question

consider the following two linear equations -2x+4y=4 "2x+8y=8" solve for the point of intersection

Answer 1

$- 2x + 4y = 4$

$2x + 8y = 8$

Add the systems together:

$2x - 2x + 4y + 8y = 4 + 8$

$12y = 12$

$y = 1$

Substitute y=1 in any equation:

$2x + 8(1) = 8$

$2x + 8 \: = 8$

$2x = 0$

$x = 0$

Define point A as the intersection between the two lines:

$a(0. \: .1)$