Question

A 15.0 cm long solenoid with radius 0.750 cm is closely wound with 600 turns of wire. the current in the windings is 8.00 a.

Answer 1

The magnetic field at a point near the center of the solenoid is equal to $4.02 \times 10^{-2}\;Tesla$

Given the following data:

• Length = 15.0 cm to m = 0.15 m.

• Radius = 0.750 cm.

• Number of turns = 600 turns.

• Current = 8.00 A.

How to calculate the magnetic field.

Mathematically, the magnetic field at a point near the center of the solenoid is given by this formula:

$B=\frac{\mu_o NI}{L}$

Where:

• $\mu_o$ is the vacuum permeability.

• N is the number of turns.

• L is the length.

• I is the current.

Substituting the given parameters into the formula, we have;

$B=\frac{4\pi \times 10^{-7} \times 600 \times 8.00}{0.15}\\\\B=4.02 \times 10^{-2}\;Tesla$

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