Question

an unknown gas at constant temperature, has a pressure of 2 atm and a volume of 7 L. Calculate the final pressure if the volume drops to 0.7 L.

Answer 1

At constant temperature, if the volume of the unknown gas drops to the given value, the pressure increases to 20.0atm.

Given the data in the question;

• Initial volume of the unknown gas; $V_1 = 7L$

• Initial pressure of the unknown gas; $P_1 = 2atm$

• Final volume of the unknown gas; $V_ 2 = 0.7L$

Final pressure of the unknown gas; $P_2 = \ ?$

Boyle's law

Boyle's law simply states that the volume V of any given quantity of gas is inversely proportional to its pressure P as long as temperature remains constant.

Boyle's law is expressed as;

$P_1V_1 = P_2V_2$

Where $P_1$ is Initial Pressure, $V_1$ Initial volume, $P_2$ is Final Pressure and $V_2$ is Final volume.

We substitute our given values into the expression above to determine the final pressure.

$P_1V_1 = P_2V_2\\\\P_2 = \frac{P_1*V_1}{V_2} \\\\P_2 = \frac{2atm\ * 7L}{0.7L} \\\\P_2 = \frac{2atm\ * 7}{0.7}\\\\P_2 = \frac{14atm}{0.7}\\\\P_2 = 20.0atm$

Therefore, at constant temperature, if the volume of the unknown gas drops to the given value, the pressure increases to 20.0atm.

Learn more about Boyle's law: brainly.com/question/1437490