I'll do the first three questions to get you started.
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Question 1
x = horizontal component of the triangle
cos(angle) = adjacent/hypotenuse
cos(theta) = horizontal/hypotenuse
cos(40) = x/30
x = 30*cos(40)
x = 22.98133329 approximately
This is the horizontal force applies to the suitcase.
Work = force*displacement
Work = 22.98133329*120
Work = 2,757.7599948
Work = 2,758
Answer: 2,758 Nm (choice B)
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Question 2
Add the drone's relative air velocity and the wind velocity vectors.
v+w = (13i + 3j) + (-7i - 2j)
v+w = (13i-7i) + (3j-2j)
v+w = 6i + j
Answer: 6i + j (choice B)
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Question 3
Check out the diagram below. Focus on the smaller triangle. Notice the placement of angle theta.
sin(theta) = opposite/hypotenuse
sin(40) = x/200
x = 200*sin(40)
x = 128.557521937308
x = 128.558
Answer: 128.558 pounds (choice A)
