Answer:
D
Step-by-step explanation:
[tex]\frac{x^2-11x+24}{(x-8)(x+2)}[/tex] ← factorise the numerator
= [tex]\frac{(x-8)(x-3)}{(x-8)(x+2)}[/tex] ← cancel the common factor (x - 8) on numerator/ denominator
= [tex]\frac{x-3}{x+2}[/tex]
