Answer:
[tex]\displaystyle [7x - 2][3x + 7][/tex]
Step-by-step explanation:
Find two quantities that when differed to 43, they also multiply to 294. Those will be 6 and 49. The TINIER quantity gets the minus symbol because the B-value is 43, therefore 49 gets the plus symbol, leaving 6 with the minus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:
[tex]\displaystyle 21x^2 + 43x - 14 \\ \\ [21x^2 - 6x] + [49x - 14] \\ 3x[7x - 2] + 7[7x - 2] \\ \\ \boxed{[7x - 2][3x + 7]}[/tex]
I am joyous to assist you at any time.
[tex]\\ \rm\rightarrowtail 21x^2+43x-14[/tex]
[tex]\\ \rm\rightarrowtail 21x^2+49x-6x-14[/tex]
[tex]\\ \rm\rightarrowtail 7x(3x+7)-2(3x+7)[/tex]
[tex]\\ \rm\rightarrowtail (7x-2)(3x+7)[/tex]
Done!
