Question

1 Figure 13.17 shows the screen of an oscilloscope. The time-base of the oscilloscope is set at 500 us div?.
Calculate the time period of the signal and hence its frequency.

Answer 1

Answer:

Explanation:

Time-base of the oscilloscope is set at 500 $\mu s$/div. It means, one block in horizontal direction represents 500 microseconds. The period of the wave is the time to complete one oscillation and in the picture there is two-block for complete one oscillation, so the period and oscillation are:

$T=(2)(500) =100 \mu s \rightarrow f=\frac{1}{T}=\frac{1}{100 \times 10^{-6}}=10000 Hz$