Answer:
See below, please
Step-by-step explanation:
The right：
[tex] {(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba = [/tex]
[tex] = {y}^{2} - bx + 2cy + {c}^{2} - ab[/tex]
The left:
[tex] = {y}^{2} - 7x - 18y + 109[/tex]
So, after comparing the right side and the left side of this equation, we know
1)
[tex]b = 7[/tex]
2)
[tex]2c = - 18 \\ so \\ c = - 9[/tex]
3)
[tex] {c}^{2} - ab = 109[/tex]
So,
[tex]a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4[/tex]
