Question

For the chemical reaction
2 NaOH + H2SO4 — Na2SO4 + 2H2O
how many moles of sodium sulfate will be produced from 28.3 g of sodium hydroxide?

Answer 1

The number of mole of sodium sulphate, Na₂SO₄ that will be produced from 28.3 g of sodium hydroxide, NaOH is 0.35 mole

How to determine the mole of NaOH

• Mass of NaOH = 28.3 g
• Molar mass of NaOH = 40 g/mol
• Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 28.3 / 40

Mole of NaOH = 0.7075 mole

How to determine the mole of Na₂SO₄ produced

2NaOH + H₂SO₄ —> Na₂SO₄ + H₂O

From the balanced equation above,

2 moles of NaOH reacted to produce 1 mole of Na₂SO₄.

Therefore,

0.7075 mole of NaOH will react to produce = (0.7075 × 1) / 2 = 0.35 mole of Na₂SO₄

Thus, 0.35 mole of Na₂SO₄ was obtained from the reaction

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