What is the approximate volume of the cone? Use 227
22
7
for π. Enter your answer in the box.

Answer :
Explanation :
We know,
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[tex]{ \longrightarrow \bf \qquad { { Volume_{(cone) }= \dfrac{1}{3} \pi {r}^{2}h }}}
[/tex]
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Where,
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Here,
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Substituting the value in the formula :
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[tex]{ \longrightarrow \sf \qquad { { Volume_{(cone) }= \dfrac{1}{3} \times \dfrac{22}{7} \times {3}^{2} \times 14 }}}[/tex]
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[tex]{ \longrightarrow \sf \qquad { { Volume_{(cone) }= \dfrac{1}{ \cancel3} \times \dfrac{22}{ \cancel7} \times { \cancel9} \times \cancel{14 }}}}[/tex]
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[tex]{ \longrightarrow \sf \qquad { { Volume_{(cone) }= 1 \times 22 \times 3 \times 2 }}}[/tex]
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[tex]{ \longrightarrow \sf \qquad { { Volume_{(cone) }= 1 \times 22 \times 6 }}}[/tex]
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[tex]{ \longrightarrow{ \pmb {\mathfrak {\qquad { Volume_{(cone) }= 132 }}}}}[/tex]
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Therefore,
Question :-
Answer :-
Explanation :-
As per the provided information in the given question, we have been given that the Radius of the Cone is 3 cm . Its Height is given as 14 cm . And, we have been asked to calculate the Volume of the Cone .
For calculating the Volume , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \sf{ \: Volume \: _{Cone} \: = \: \frac{1}{3} \: \pi {r}^{2} h \: }} [/tex]
Where ,
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf{Volume \: _{Cone} \: = \: \dfrac{1}{3} \: \times \: \pi \: \times \: {r}^{2} \: \times \: h } [/tex]
[tex] \longmapsto \: \: \sf{Volume \: _{Cone} \: = \: \dfrac{1}{3} \: \times \: \dfrac{22}{7} \: \times \: ( {3})^{2} \: \times \: 14 } \\ [/tex]
[tex] \longmapsto \: \: \sf{Volume \: _{Cone} \: = \: \dfrac{1}{3} \: \times \: \dfrac{22}{7} \: \times \: 9 \: \times \: 14 } \\ [/tex]
[tex] \longmapsto \: \: \sf{Volume \: _{Cone} \: = \: \dfrac {1}{1} \: \times \: \dfrac {22}{1} \: \times \: 3 \: \times \: 2 } [/tex]
[tex] \longmapsto \: \: \sf {Volume \: _{Cone} \: = \: 1 \times \: 22 \: \times \: 3 \: \times \: 2} [/tex]
[tex] \longmapsto \: \: \sf {Volume \: _{Cone} \: = \: 1 \times \: 22 \: \times \: 6} [/tex]
[tex] \longmapsto \: \: \sf {Volume \: _{Cone} \: = \: 22 \: \times \: 6} [/tex]
[tex] \longmapsto \: \: \bf {Volume \: _{Cone} \: = \: 132 \: cm } [/tex]
Hence :-
[tex] \underline {\rule {200pt} {4pt}} [/tex]