Question

hello people ~
factorise: x ^ 2 = 17x + 60​

Answer 1

Answer:

$\rightarrow \sf x^2=\:17x\:+\:60$

change sides

$\rightarrow \sf x^2 -17x -60 = 0$

breakdown, (60 : 20 * 3)

$\rightarrow \sf x^2 -20x +3x-60 = 0$

factor the following

$\rightarrow \sf x(x -20) +3(x-20) = 0$

collect into groups

$\rightarrow \sf (x +3)(x-20) = 0$

final answer

$\rightarrow \sf x=-3, \ 20$

Answer 2

Answer:

(x-20) (x+3) =0

Step-by-step explanation:

x ^ 2 = 17x + 60​

Subtract 17x from each side

x ^ 2 - 17x = 60​

Subtract 60 from each side

x ^ 2 - 17x - 60=0

What 2 numbers multiply by -60 and add to -17

-20 * 3 = -60

-20 +3 = -17

(x-20) (x+3) =0

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