Answer:
[tex]y=14x^2+x-3[/tex]
Step-by-step explanation:
If the zeros of the polynomial are -1/2 and 3/7 then:
[tex]\implies x=-\dfrac12[/tex]
Add 1/2 to both sides:
[tex]\implies x+\dfrac12=0[/tex]
Multiply both sides by 2:
[tex]\implies 2x+1=0[/tex]
[tex]\implies x=\dfrac37[/tex]
Subtract 3/7 from both sides:
[tex]\implies x-\dfrac37=0[/tex]
Multiply both sides by 7:
[tex]\implies 7x-3=0[/tex]
Therefore, the factored form of the polynomial is [tex]y=(2x+1)(7x-3)[/tex]
Expanding the brackets so that the polynomial is in standard form:
[tex]\implies y=14x^2-6x+7x-3[/tex]
[tex]\implies y=14x^2+x-3[/tex]