Respuesta :

Answer:

Yes, the sequence is geometric

common ratio (r) = -3

Step-by-step explanation:

Given:

  • [tex]a_1=1[/tex]
  • [tex]a_2=-3[/tex]
  • [tex]a_3=9[/tex]
  • [tex]a_4=-27[/tex]

If a sequence is geometric, common ratio [tex]r[/tex]:

[tex]r=\dfrac{a_4}{a_3}=\dfrac{a_3}{a_2}=\dfrac{a_2}{a_1}[/tex]

Substituting the given values:

[tex]\implies \dfrac{a_4}{a_3}=\dfrac{-27}{9}=-3[/tex]

[tex]\implies \dfrac{a_3}{a_2}=\dfrac{9}{-3}=-3[/tex]

[tex]\implies \dfrac{a_2}{a_1}=\dfrac{-3}{1}=-3[/tex]

Therefore, as

[tex]\dfrac{a_4}{a_3}=\dfrac{a_3}{a_2}=\dfrac{a_2}{a_1}=-3[/tex]

the sequence is geometric with common ratio of -3

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