Answer:
Yes, the sequence is geometric
common ratio (r) = -3
Step-by-step explanation:
Given:
If a sequence is geometric, common ratio [tex]r[/tex]:
[tex]r=\dfrac{a_4}{a_3}=\dfrac{a_3}{a_2}=\dfrac{a_2}{a_1}[/tex]
Substituting the given values:
[tex]\implies \dfrac{a_4}{a_3}=\dfrac{-27}{9}=-3[/tex]
[tex]\implies \dfrac{a_3}{a_2}=\dfrac{9}{-3}=-3[/tex]
[tex]\implies \dfrac{a_2}{a_1}=\dfrac{-3}{1}=-3[/tex]
Therefore, as
[tex]\dfrac{a_4}{a_3}=\dfrac{a_3}{a_2}=\dfrac{a_2}{a_1}=-3[/tex]
the sequence is geometric with common ratio of -3