This is urgent I really I need the answers
Thanks in advance

equation: 2y = 3x + 15
If cross y-axis, the x will be 0
2y = 3(0) + 15
2y = 15
y = 7.5
crosses y-axis at (0, 7.5)
(b)
P(-1,10), Q(3,4)
(i) gradient:
[tex]\sf \dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\rightarrow \sf \dfrac{4-10}{3--1}[/tex]
[tex]\rightarrow \sf \dfrac{-6}{4}[/tex]
[tex]\rightarrow \sf -1.5[/tex]
(ii) midpoint:
[tex]\sf (x_m, y_m) = (\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})[/tex]
[tex]\rightarrow \sf (x_m, y_m) = (\dfrac{3-1}{2}, \dfrac{4+10}{2})[/tex]
[tex]\rightarrow \sf (x_m, y_m) = (1,7)[/tex]